Respuesta :

sarah0182
Let x = the number of marbles for Phil
Then 3x = the number of marbles for Peter
Together they have 3x+x=48 or 4x=48 and x=12
So Phil has x = 12 marbles and Peter has 3x, let x = 12, 3(12) = 36 marbles.
Peter has 24 more marbles than Phil.
Lanuel

Phil has 24 more rocks than Peter.

  • Let the number of Phil's rock be H.
  • Let the number of Peter's rock be P.

Given the following data:

  • Total number of rocks = 48 rocks

To find how many more rocks Phil has than Peter:

Translating the word problem into an algebraic expression, we have;

[tex]H = 3P[/tex]    ....equation 1

[tex]H + P = 48[/tex]  ....equation 2

Substituting eqn 1 into eqn 1, we have;

[tex]3P + P = 48\\\\4P = 48\\\\P = \frac{48}{4}[/tex]

Peter = 12 rocks.

For Phil:

[tex]H = 3P\\\\H = 3(12)[/tex]

Phil, H = 36 rocks

To find the difference:

[tex]36 - 12 = 24[/tex]

Therefore, Phil has 24 more rocks than Peter.

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