A copper sulphate solution contained 0.100 moles of copper sulphate dissolved in 0.500 dm cubed of water. Calculate the mass of copper sulphate in 30.0cm cubed of this solution. Relative formula mass (mr): CuSO4= 159.5

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NvmMan21 NvmMan21 · Answer 1 · 2021-12-01T17:21:43+01:00

Answer:

cm^3 —> dm^3

divide by 1000

159.5 — Mr of CuSO4

n (moles in mol) = c (concentration in mol/dm^3) * v (volume in dm^3)

0.100 mol of CuSO4 dissolved in 0.5dm^3 of water

calculate for mass of CuSO4 dissolved in 0.03dm^3 (30cm^3) of the solution

n = m/Mr

m = n*Mr

if 0.1 mol is dissolved in 0.5 dm^3 of water

0.5/0.03 ≈ 16.66666667

0.1 = 0.05

0.1 / 16.66666667 = 0.006

0.5 / 16.66666667 = 0.03

0.006 (mol of CuSO4) = 0.03 (dm^3 solution)

0.006 * 159.5 = 0.957 g

I think this is the answer

priyankapandeyVT priyankapandeyVT · Answer 2 · 2022-05-24T10:27:47+02:00

The mass copper sulphate CuSO₄ in 30ml solution is 957.6g.

To determine the mass of copper sulphate in the given solution, compare both the molarity given

M₁V₁=M₂V₂

n₁/V1=n₂/V2

0.1/0.5=n₂/30 cm³=ml

n₂=6 moles

6×159.5=957.6g

Multiply the calculated moles with the relative mass/molecular mass to get the mass of CuSO₄.

hence, the mass of CuSO₄ is 957.6g

Learn more about dilution equation.

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