A cubical block of wood, 10.0 cm on a side, floats at the interface between oil and water with its lower surface 1.50 cm below the interface (Fig. E12.33). The density of the oil is 790 kg>m3 . (a) What is the gauge pressure at the upper face of the block

Respuesta :

Answer:

the gauge pressure at the upper face of the block is 116 Pa

Explanation:

Given the data in the question;

A cubical block of wood, 10.0 cm on a side.

height h = 1.50 cm = ( 1.50 Ɨ ( 1 / 100 ) ) m = 0.0150 m

density ρ = 790 kg/m³

Using expression for the gauged pressure;

p-pā‚€ = ρgh

where, pā‚€ is atmospheric pressure, ρ is the density of the substance, g is acceleration due to gravity and h is the depth of the fluid.

we know that, acceleration due to gravity g = 9.8 m/s²

so we substitute

p-pā‚€ = 790 kg/m³gh Ɨ 9.8 m/s² Ɨ 0.0150 m

= 116.13 ā‰ˆ 116 Pa

Therefore, the gauge pressure at the upper face of the block is 116 Pa