Answer:
electric flux through the entire Gaussian surface will be positive ( + )
Explanation:
The dipole is surrounded by Gaussian surface of charge q
The electric flux will be  positive
i.e.  Ф = E. ds  since the surface is a close one the direction of the area outwardly will be positive . therefore the angle between  E and A < 90°
Hence the  electric flux through the entire Gaussian surface will be positive