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Soda pop cane are made of aluminum having thickness of 0.12 mm. They are typically kept at a temperature of 4Ā°C in refrigerator. Such cane has height of 4.83 inch and diameter of 2.6 inch. Suppose you bought such a cold soda pop and brought into the class where the temperature is 25Ā°C.

Required:
Calculate the rate of heat transfer of the coke cane to the surroundings.

Respuesta :

Answer:

Explanation:

For flow of heat through conduction , the formula is

Q = KA( Tā‚‚ -Tā‚ ) / d where K is thermal conductivity of material , A is surface area , Tā‚‚ - Tā‚ is temp diff .

Thermal conductivity of aluminum is 205 W /m.s

Surface area of cane = 2Ļ€ rĀ² + 2Ļ€ r h where r is radius and h is height of cane .

A = 2Ļ€ r ( r + h )

= 2 x 3.14 x 1.3 x .0254 ( 1.3 x .0254 + 4.83 x .0254 )

= .20736 ( .033 + .12268 )

A = .03228 mĀ²

thickness d = .12 x 10ā»Ā³ m

Putting the values ,

Q = 205 x .03228 x ( 25 - 4 ) / .12 x 10ā»Ā³

= 1158 x 10Ā³ J /s

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