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Create a function called makePositive that accepts a single argument: an integer array. The function should walk through the array and change any negative numbers to positive. You can assume that the array passed to the function will have a 0 at the end of the array. In other words, you do not know the size of the array; you instead know that a certain condition will be true at the end of the array.

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MrRoyal

Answer:

This solution is implemented in C++

void makePositive(int arr[]){

   int i =0;

   while(arr[i]!=0){

       if(arr[i]<0){

           arr[i] = abs(arr[i]);

       }

       i++;

   }

   i = 0;

   while(arr[i]!=0){

    cout<<arr[i]<<" ";

    i++;

}  

}

Explanation:

This defines the function makePositive

void makePositive(int arr[]){

This declares and initializes i to 0

   int i =0;

The following iteration is repeated until the last element in the array

   while(arr[i]!=0){

This checks if current array element is negative

       if(arr[i]<0){

If yes, it changes it to positive

           arr[i] = abs(arr[i]);

       }

The next element is then selected

       i++;

   }

This sets i to 0

   i = 0;

The following iteration prints the updated content of the array

   while(arr[i]!=0){

    cout<<arr[i]<<" ";

    i++;

}  

}

See attachment for full program which includes the main

Ver imagen MrRoyal

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