Answer:
a
The force is  [tex]F = 2864561.4 \ N[/tex]
b
The number is [tex]N = 3248 \ players[/tex]
Explanation:
From the question we are told that
  The  of each cylinder is  [tex]d = 60 \ cm = 6 \ m[/tex]
   The mass of the players is  [tex]m = 90 \ kg[/tex]
Generally the cross-sectional  area of the cylinder is mathematically represented as
   [tex]A = \pi * \frac{d^2}{4}[/tex]
=> Â [tex]A = 28.3 \ m^2[/tex]
Generally force exerted on the flat end of each cylinder is mathematically represented as
   [tex]F = A * P[/tex]
Here P  is the atmospheric pressure with value  [tex]P = 101300 \ Pa[/tex]
So
    [tex]F = 28.3 * 101300[/tex]
=> Â Â [tex]F = 2864561.4 \ N[/tex]
Generally the weight of a single football player is Â
    [tex]W = m * g[/tex]
=> Â Â [tex]W = 90 * 9.8[/tex]
=> Â Â [tex]W = 882\ N[/tex]
Generally the number of player required to pull the two cylinders apart is mathematically represented as
    [tex]N = \frac{ F }{W}[/tex]
=> Â Â [tex]N = \frac{ 2864561.4 }{882}[/tex]
=> Â Â [tex]N = 3248 \ players[/tex]
