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A cylinder, with a piston pressing down with a constant pressure, is filled with 2.10 moles of a gas (n1), and its volume is 46.0 L (V1). If 0.700 mole of gas leak out, and the pressure and temperature remain the same, what is the final volume of the gas inside the cylinder?

Respuesta :

okpalawalter8

Answer:

The volume is  [tex]V_2 =15.33 \ L[/tex]

Explanation:

From the question we are told that

    The number of moles of the gas is  [tex]n_1 = 2.10 \ moles[/tex]

      The volume of the gas is  [tex]V = 46.0 \ L[/tex]

        The  of moles of the gas that leaked is  [tex]n_2 = 0.700 \ mol[/tex]

Generally from the ideal gas law

      [tex]PV = nRT[/tex]        

Generally at constant pressure and temperature

        [tex]\frac{V}{n} = constant[/tex]

So   [tex]\frac{V_1 }{n_1} = \frac{V_2 }{n_2}[/tex]

=>    [tex]V_2 = \frac{ V_1 * n_2 }{ n_1}[/tex]

=>    [tex]V_2 = \frac{ 46.0 * 0.700 }{ 2.10 }[/tex]  

=>    [tex]V_2 =15.33 \ L[/tex]

             

     

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