Answer:
(a) 165.46 V
(b) 7.78 A
Explanation:
(a) From the question,
Vrms = Vā/ā2...................... Equation 1
Where Vā = maximum potential difference across a lamp connected to the outlet.
make Vā the subject of the equation.
Vā = ā2(Vrms)............... Equation 2
Given: Vrms = 117 V.
Substitute into equation 2
Vā = (ā2)(117)
Vā = 165.46 V.
(b) Similarly,
Iā = ā2(Irms)....................... Equation 3
Given: Irms = 5.5 A
Substitute into equation 3
Iā = (ā2)(5.5)
Iā = 7.78 A.
