Respuesta :
Answer:
Distance from the second drop is 81.5 cm
Distance from the third drop is 20.5 cm
Explanation:
Given total height = 184 cm = 1.84 m
  By using second equation of motion we can find the total time of drop to reach the ground
            s = vi +(1/2) a×t²
s stands for distance or height
vi stands for initial velocity
t stands for time
a stands for gravitational constant
             s= 1.84 m
             vi= 0 m/s
             g = 9.8 m/s²
            s= vi +(1/2) a×t²
          1.84 = 0 +(1/2)×9.8×t²
          1.84 = 4.9 ×t²
            t = 0.612 s
The time interval for each drop is equal so 4 drops there are 3 time intervals. We can find the time interval by dividing the total time by 3.
           time interval = total time/ 3
                      = 0.612/3
                      = 0.204 s
Part a : Distance from the second drop
                 t=2× time interval
                 t = 2 × 0.204
                 t = 0.408 s
            s = vi+ (1/2)a×t²
            s = 0 + (1/2) 9.8×(0.408)²
            s = 4.9×0.166
            s = .815 m = 81.5 cm
Distance from the second drop is 81.5 cm
Part b : Distance from the third drop
           t= time interval
           t = 0.204 s
           s = vi + (1/2) a×t²
           s = 0 + 0.5×9.8×(0.204)²
           s = 4.9×0.042
           s = 0.205 m = 20.5 cm
Distance from the third drop is 20.5 cm
