Answer:
600 mL
Explanation:
The volume of 10% acid solution used to make the mixture = 200 L
Let the volume of 30% acid solution used to make the mixture = x mL
Total volume of the mixture = (200+ x) mL
For 10% acid solution:
Cā = 10% , Vā = 200 mL
For 30% acid solution :
Cā = 30% , Vā = x mL
For the resultant solution of sulfuric acid:
Cā = 25% , Vā = (200 + x) mL
Using Ā
CāVā + CāVā = CāVā
10Ć200 + 30Ćx = 25Ć(200 + x)
Solving for x,
x = 600 mL
600 milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 25 percent alcohol by volume.
