02-08-2019
Mathematics

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A sample of 3 different bulbs is randomly selected from a group containing 8 that are defective and 22 that have no defects. What is the probability that at least one of the bulbs is defective?Round answer to three decimal places.

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02-08-2019

Answer:

Probability of drawing non defective bulb

=90/100×89/99×88/98×...........×82/92..........(i)=90/100×89/99×88/98×...........×82/92..........(i)

Now the probability of drawing at least one bulb will be defective

=1−(i)=1−90/100×89/99×88/98×...........×82/92

1−(90/100⋅89/99⋅…⋅83/93)

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