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A research biologist requires a sturdy yet floatable plastic sphere to carry out a lake project within a local wildlife refuge.the spheres have a diameter of 51.75mm what is the maximum allowable mass the sphere can be in order to remain afloat ? Assume the density of water in the lake is 1.0 g/cm^3 at all times throughout the year

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The maximum allowable mass is 580 g.

Step 1. Calculate the volume of the spheres

V = (4/3)πr^3 = (4/3)π × (51.75 mm^3) = 5.8052 × 10^5 mm^3

Step 2. Convert the volume to cubic centimetres

V = 5.8052 × 10^5 mm^3 × (1 cm/10 mm)^3 = 580.52 cm^3

Step 3. Calculate the mass of water displaced

According to Archimedes’ principle, each sphere displaces

580.52 cm^3 water

Mass of water = 580.52 cm^3 water × (1.0 g water/1 cm^3) = 580 g water

If the mass of a sphere is greater than the mass of water displaced, the sphere will sink.

∴ The maximum allowable mass of the sphere is 580 g.

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